The electronic configuration of Ca is
1s2 2s2 2p6 3s2 3p6 4s2 3d10.
Since, calcium has 20 electrons, it can lose 2 electrons to attain electronic configuration of argon to attain stability. So it will lose 2 electrons from its outermost subshell i.e., 4s2
Ca → Ca2+ + 2e-
The electronic configuration of Cl is
1s2 2s2 2p6 3s2 3p5.
Since chlorine is 17 electrons, it can gain 1 electron to to attain electronic configuration of argon to attain stability. So it will gain 1 electron.
Cl + 1e- → Cl-.
Since, Calcium loses 2 electrons, so 1 electron will be gained by one chlorine atom and other by 2 chlorine atom. So 1 calcium ion will bind with 2 chloride ions.
Ca2+ + 2Cl- → CaCl2
Hence, option B is correct.
The electronic configuration of Ca is
1s2 2s2 2p6 3s2 3p6 4s2 3d10.
Since, calcium has 20 electrons, it can lose 2 electrons to attain electronic configuration of argon to attain stability. So it will lose 2 electrons from its outermost subshell i.e., 4s2
Ca → Ca2+ + 2e-
The electronic configuration of Cl is
1s2 2s2 2p6 3s2 3p5.
Since chlorine is 17 electrons, it can gain 1 electron to to attain electronic configuration of argon to attain stability. So it will gain 1 electron.
Cl + 1e- → Cl-.
Since, Calcium loses 2 electrons, so 1 electron will be gained by one chlorine atom and other by 2 chlorine atom. So 1 calcium ion will bind with 2 chloride ions.
Ca2+ + 2Cl- → CaCl2
Hence, option B is correct.