Use the given standard enthalpies of formation to determine the heat of reaction of the reaction:C3H6O(l) + 4O2(g) → 3 CO2(g) + 3 H2O(l)ΔH°f CO2(g) = -394 kJ/moleΔH°f H2O(l) = -286 kJ/moleΔH°f C3H6O(l) = -250 kJ/mole

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Use the given standard enthalpies of formation to determine the heat of reaction of the reaction:C3H6O(l) + 4O2(g) → 3 CO2(g) + 3 H2O(l)ΔH°f CO2(g) = -394 kJ/moleΔH°f H2O(l) = -286 kJ/moleΔH°f C3H6O(l) = -250 kJ/mole