A fisherman lifts a fish of mass 250 g from rest through a vertical height of 1.8 m. The fish gains a speed of 1.1 m/s. What is the energy gained by the fish?

MCQS

UHS MDCAT 2023

Q-182

Jump to Deck

<p>A fisherman lifts a fish of mass 250 g from rest through a vertical height of 1.8 m. The fish gains a speed of 1.1 m/s. What is the energy gained by the fish?</p>

Physics

Miscellaneous

Question 182 of 200

Multiple Choice

0.15 J

18.30%

Explanation:

This option suggests an energy of 0.15 J, which is significantly lower than the calculated value.

4.3 J

17.72%

Explanation:

This option suggests an energy of 4.3 J, which is close to the calculated value.

4.4 J

39.49%

Explanation:

This option suggests an energy of 4.4 J, which is close to the calculated value.

4.6 J

24.48%

Explanation:

This option suggests an energy of 4.6 J, which is close to the calculated value.

Explanation

The question involves calculating the energy gained by a fish when lifted by a fisherman through a vertical height.To calculate the energy gained, we can use the formula for gravitational potential energy:

PE=mgh

Where:

PE is the potential energy gained (in joules, J)

m is the mass of the fish (in kilograms, kg)

g is the acceleration due to gravity (approximately 9.81 m/s²)

h is the height the fish is lifted (in meters, m)

Given:

Mass of the fish (m) = 250 g = 0.25 kg

Height (h) = 1.8 m

Now, we'll calculate the potential energy gained by the fish:

=4.4325J

The correct answer is C. 4.4 J. This value is very close to the calculated potential energy of the fish.